设猴子为x,狗为y,猫为z;根据题干可得: x*x=y,x+y=z,10+z=30;换算可得: z=20,y=20-x,x*x=20-x;进一步可得: x(x+1)=20排除法得知:x=4,上推得:y=16,z=20.所以结果为:猴子是4,狗是16,猫是20.
设猴子为x,狗为y,猫为z;根据题干可得: x*x=y,x+y=z,10+z=30;换算可得: z=20,y=20-x,x*x=20-x;进一步可得: x(x+1)=20排除法得知:x=4,上推得:y=16,z=20.所以结果为:猴子是4,狗是16,猫是20.
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