
2=1x3-1,
7=2x3+1
23=7x3+2
76=23x3+7
规律为:a(n+1)=anx3+a(n-1), (这里假设有第0项为-1)
所以76后面的项为:251
251=76x3+23

2=1x3-1,
7=2x3+1
23=7x3+2
76=23x3+7
规律为:a(n+1)=anx3+a(n-1), (这里假设有第0项为-1)
所以76后面的项为:251
251=76x3+23
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