Keener_Tic_Tac_Toe（井字棋游戏）代码(c语言）

遇到的问题:

1.中间有需要清楚键盘缓冲区,具体(?)

2.number char型,强制int型转换是利用ASCII码,相差48.

3.string型c 支持,c并没有,利用char型字符数组解决,char player1[20];scanf("%s",player1);printf("%s",player1);

代码如下:

1. 
   
2. #include <stdio.h>
3. #include <ctype.h>
4. #include <stdbool.h>
5. #include <stdlib.h>
6. #include <time.h>
9. int main(){
11. //初始化
12. char another_game = 'Y';
13. char game[3][3] = {{'1','2','3'},{'4','5','6'},{'7','8','9'}};
14. bool win = true;
15. int choose_player = 0;
16. char number = '0';
17. int row = 0 , col = 0;
18. bool take_turns = false;
19. char player1[20],player2[20];
20. int c;
22. //循环_1
23. do{
24. //初始化游戏
25. printf("井字棋游戏初始化...\n");
26. char game[3][3] = {{'1','2','3'},{'4','5','6'},{'7','8','9'}};
27. win = false;
29. //输入玩家1,2姓名
30. printf("(不要使用空格,回车键结束)\n");
31. printf("请输入玩家1姓名:\n");
32. scanf("%s",player1);
33. printf("请输入玩家2姓名:\n");
34. scanf("%s",player2);
36. //随机选择先落子玩家
37. srand((unsigned)time(NULL));
38. choose_player = rand()%2 1;
39. if(choose_player == 1){
40. take_turns = true;
41. printf("%s(玩家1)首先落子(1~9).\n",player1);
42. }else{
43. take_turns = false;
44. printf("%s(玩家2)首先落子(1~9).\n",player2);
45. }
47. //循环_2
48. while(!win){
49. //输出3x3游戏格
50. printf("\n");
51. printf(" %c | %c | %c \n",game[0][0],game[0][1],game[0][2]);
52. printf("--- --- ---\n");
53. printf(" %c | %c | %c \n",game[1][0],game[1][1],game[1][2]);
54. printf("--- --- ---\n");
55. printf(" %c | %c | %c \n",game[2][0],game[2][1],game[2][2]);
56. printf("\n");
59. //玩家1,玩家2分别下棋
60. //落子是否有效
61. do{
62. printf("%s落子:",take_turns?player1:player2);
63. //这里需要清楚缓冲区(why?)
64. if(fEOF(stdin) || ferror(stdin)){
65. break;
66. }
67. while((c = getchar()) != '\n' && c != EOF);
68. scanf("%c",&number);
70. //why:ASCII码表对应的数字差48~
71. row = ((int)number-48-1)/3;
72. col = ((int)number-48-1)%3;
73. //printf("%d.%d.%c.\n",row,col,game[row][col]);
74. //printf("%c\n",number);
75. }while( game[row][col] != number);
77. //更新棋盘
78. if(take_turns){
79. game[row][col] = 'X';
80. }else{
81. game[row][col] = 'O';
82. }
84. //循环_2,判定:是否有人胜利
85. if((game[0][0] == game[0][1] && game[0][1] == game[0][2])||
86. (game[1][0] == game[1][1] && game[1][1] == game[1][2])||
87. (game[2][0] == game[2][1] && game[2][1] == game[2][2])||
88. (game[0][0] == game[1][0] && game[1][0] == game[2][0])||
89. (game[0][1] == game[1][1] && game[1][1] == game[2][1])||
90. (game[0][2] == game[1][2] && game[1][2] == game[2][2])||
91. (game[0][0] == game[1][1] && game[1][1] == game[2][2])||
92. (game[0][2] == game[1][1] && game[1][1] == game[2][0])
93. ){
94. win = true;
95. printf("%s胜利!游戏结束.",take_turns?player1:player2);
97. printf("\n");
98. printf(" %c | %c | %c \n",game[0][0],game[0][1],game[0][2]);
99. printf("--- --- ---\n");
100. printf(" %c | %c | %c \n",game[1][0],game[1][1],game[1][2]);
101. printf("--- --- ---\n");
102. printf(" %c | %c | %c \n",game[2][0],game[2][1],game[2][2]);
103. printf("\n");
104. }else{
106. if(take_turns){
107. take_turns = false;
108. }else{
109. take_turns = true;
110. };
111. }
113. }
114. //循环_1,是否开始新游戏
115. if(feof(stdin) || ferror(stdin)){
116. break;
117. }
118. while((c = getchar()) != '\n' && c != EOF);
119. printf("是否开始新游戏?(y/n)");
120. scanf("%c",&another_game);
121. }while(toupper(another_game)=='Y');
122. //结束
123. return 0;
124. }